It is stable. The highest bond order you can get is for an sp hybridized N atom in each example. Br has 7 valence electrons, so Br2 should have 14. Your dashboard and recommendations. This gives you have a triple bond for N2+, N2, and N2 2+. Sketch the molecular orbital energy’ level diagram for the ion and the e. Switch to. Unanswered Questions. Homework Help. Br2 2+ should be paramagnetic because when you remove the 2 electrons, the 3pi-x and 3pi-y will be unpaired, like Shreyesi said. Booster Classes. Home. Test Series. Each hydrogen atom contributes one 1s atomic orbital, and thus, the orbitals overlap according to MO theory to form one sigma_(1s) and one sigma_(1s)^"*" MO by conservation of orbitals. Get the detailed answer: Calcium carbide, CaC2, contains the acetylide ion, C22 −. Each hydrogen atom contributes one electron, and thus, "H"_2^(-) has three electrons while "H"_2^(+) has one. In fact, it's the perioxide ion.Check me out: http://www.chemistnate.com (I) Bond order of CO and N 2 are 3 and 3 (II) Bond order of CO and N 2 are same (III) During the formation of N 2 + from N 2 bond length increases (IV) During the formation of C O + from CO, the bond … I'm assuming you mean "H"_2^(-) vs. "H"_2^(+). Well, build the molecular orbital (MO) diagram. It is sigma2s(2)sigma2s*(2)sigma2p(2)pi2p(4)pi2p*(4)Bond order 1. Bond order==Nb-Na2Thus, the correct order of bond order is,He2+